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Old Feb 26, 2011, 10:55 AM   #1
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Default Sensor size question

The reason I purchased an S90 was the larger sensor size (compared to most P&S's). The S90 has a sensor that is described in size as 1/1.7". The Olympus ZX-1 has a sensor size that is described as 1/1.63". I would appreciate it if someone can explain what these ratios mean. i.e.
a. Does the ratio some how refer to the physical dimensions of the sensor? If so, what?
b. Does 1/1.63" represent a larger sensor than the S90's 1/1.7"?


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Old Feb 26, 2011, 11:59 AM   #2
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Look here:

http://www.dpreview.com/learn/?/key=sensor+sizes

http://sensor-size.com/
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Old Feb 26, 2011, 12:13 PM   #3
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Thanks Ordo.... The convention makes no sense at all, but the conclusion for me is that a smaller denominator indicates a larger sensor. I'm puzzled as to why Canon and Olympus don't pick a simpler way of explaining this matter since it is the key to the better performance of the S90/S95 and the ZX1.
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Old Feb 26, 2011, 1:06 PM   #4
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Then you have sensor type, sensor size, pixel density, aspect ratio, lens luminosity, ISO capability, etc. The new Olympus seems to have a f/1.8 lens, which is awesome for a ps. Much better than the S90 sensor? I don't know. Picks from S90 and S95 are just amazing.
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Old Feb 26, 2011, 2:08 PM   #5
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G'day JP

You're right mate - there is no logic whatsoever to those silly fractional numbers
As cameras are international sales items, the easiest and simplest way to describe them 'should' be in millimetres

Regards, Phil
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Old Feb 26, 2011, 3:30 PM   #6
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Quote:
Originally Posted by Ozzie_Traveller View Post
G'day JP

You're right mate - there is no logic whatsoever to those silly fractional numbers
As cameras are international sales items, the easiest and simplest way to describe them 'should' be in millimetres

Regards, Phil
Amen to that Phil!!

Thanks!
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