Quote:
Originally Posted by Bynx
Well, two pretty smart guys duking it out over the sun and the sky. How about answering the question. I think its an important one and should be easy enough to answer. Its a technical question and should apply to all cameras.
OK, while I could go on about atmospheric refraction and how it has nothing to do with the whiteness of the light source, let me try to contribute to an answer for the original question.
I would suggest, for starters, to consult definitions of illuminance and EV.
Illuminance is measured in lux, defined as 1 lumen per square meter. It is therefore a measure of light flux per unit area.
See also:
http://en.wikipedia.org/wiki/Illuminance
From there, I quote:
Quote:
The human eye is capable of seeing somewhat more than a 2 trillion-fold range: The presence of white objects is somewhat discernible under starlight, at 5×10^−5 lux, while at the bright end, it is possible to read large text at 10^8 lux, or about 1,000 times that of direct sunlight, although this can be very uncomfortable and cause long-lasting afterimages.
There is also a table of typical lux values at
http://en.wikipedia.org/wiki/Lux
On the other hand, EV is a scale based on factors of 2, so for every EV step, the amount of incident light doubles.
Comparing 10^−5 lux (starlight) to 10^5 lux (direct sunlight), this is a factor of 10^10. On a scale of powers of 2, this corresponds to about 30 EV steps.
Remember that the scale is open on both ends, so in terms of illuminance, a truly "black box" would read "ten to the power of negative infinity". So that's not really practical. You have to choose a lower and upper threshold, which is what I've tried to do with the examples from the lux table.
Caveat: illluminance is not the same as irradiance, which measures the physical power of the radiation. I'm not sure inasfar one should rather use irradiance to do the above calculation.
Also, none of us would use the same camera settings to shoot direct sunlight and a closed box. So I'm actually not quite sure I understand the "actual question", Bynx.
If there are photons, no matter how few, if you leave your aperture open for long enough, you'll get a picture. Conversely, if you make your aperture small enough and your shutter fast enough, direct sunlight won't over-saturate your sensor.
So what exactly
is the question that we're supposed to answer?
Regards,
Mark