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Old Mar 3, 2010, 6:36 PM   #71
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By the way, what's the definition of "photosensitive?"
What does "Mr. Dictionary" have to say?
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Old Mar 4, 2010, 5:45 PM   #72
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What does "Mr. Dictionary" have to say?
Sensitive to light or any other kind of radiation.

A modeling program uses electric energy to store images on a memory chip.

IBM is about to release memory chips that will be powered by photons, instead of electrons.

A digital sensor converts photons into electric energy...

Hmm?

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Old Mar 4, 2010, 6:52 PM   #73
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A modeling program uses electric energy to store images on a memory chip.
No. A modeling program manipulates values. The operating system stores those values in either volatile memory or non-volatile memory.

Because the modeling program is in volatile memory, it would use electrical energy even if the image didn't change. So the image isn't recorded by the modeling program, and the expenditure of electrical energy has nothing to do with the image. The modeling program would use electrical energy even if it didn't have an image to work with.

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IBM is about to release memory chips that will be powered by photons, instead of electrons.
But those photons aren't part of the image. They're volatile memory that contains the values than the modeling program uses to create an image. The number of photons used is constant regardless of the actual values they store. In an actual photographic image, more photons would result in a brighter image. Not so in a modeling program.
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Old Mar 5, 2010, 6:39 PM   #74
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No. A modeling program manipulates values. The operating system stores those values in either volatile memory or non-volatile memory.

Because the modeling program is in volatile memory, it would use electrical energy even if the image didn't change. So the image isn't recorded by the modeling program, and the expenditure of electrical energy has nothing to do with the image. The modeling program would use electrical energy even if it didn't have an image to work with.



But those photons aren't part of the image. They're volatile memory that contains the values than the modeling program uses to create an image. The number of photons used is constant regardless of the actual values they store. In an actual photographic image, more photons would result in a brighter image. Not so in a modeling program.
All this from a guy who uses a camera, that in turn uses a built in computer to translate gray into color...

I really think you ought to go back to film, since your images are all interpolations of electric energy from a grid of sensors, manipulated by volatile memory...

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Old Mar 5, 2010, 6:55 PM   #75
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Why is it you guys cant agree on anything? Surely neither of you can argue the point that an image created completely by computer when printed out or displayed on a monitor can be called a photograph. A photograph has some realm of reality. It started in the real world at some point. It crosses into the computer world of bits and bytes (numbers). When the numbers are played with and the image is printed or displayed on a monitor is it still a photograph. How many numbers have to be altered before you can no longer call it a photograph and refer to it as digital art?

Photo contests have a category for Best Photo and also one for Best Digital Art. At what point does the definition blur?

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Old Mar 5, 2010, 6:59 PM   #76
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Photo contests have a category for Best Photo and also one for Best Digital Art. At what point does the definition blur?

i think this is the problem. that line blurs at different points for different people.
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Old Mar 6, 2010, 2:54 PM   #77
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i think this is the problem. that line blurs at different points for different people.
TCav is trying to bang into my head the concept that to take a photograph, you need a camera.

There is a kind of photography where you go into your dark room, lay an object on photographic paper, and expose it to a controlled amount, and angle of light.

There is another form of photography where you build a box, drill a hole in one end, and expose your film via the pinhole. Perfectly acceptable forms of photography.

And todays "photosensitive" surface consists of little holes, which can only measure intensity of light, and you literally NEED a computer to provide algorhytms to decide which color is which. No on board computer - No picture.

At this point in time, where you can literally do Anything to an image with your computer, isn't all of this academic?

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Old Mar 6, 2010, 3:48 PM   #78
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TCav is trying to bang into my head the concept that to take a photograph, you need a camera
No. I'm trying to bang into your head the concept that to take a photograph, you need a phtosensitive surface.

If the image didn't originate from a photosensitive surface, it's not a photograph. Anything and everything that happens after that may or may not alter its status as a photograph, but it starts with a photosensitive surface.
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Old Mar 6, 2010, 4:09 PM   #79
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A contact print is not a photograph. A pinhole camera is still a camera.
You do need a camera to make a photograph.

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Old Mar 6, 2010, 4:17 PM   #80
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But a camera that doesn't contain a photosensitive surface can't make a photograph. To make a photograph, all you need is a photosensitive surface. And if you don't have a photosensitive surface, you can still make some very nice images, but they're not photographs.
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