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Old Jan 25, 2011, 4:29 AM   #21
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Hi Eric,

I've had very good success enlarging photographs by first running the image through Adobe's Camera RAW 6.3 and choosing the largest file size it can deliver. I then open the image in CS5 and run the Gen. Fractals plug-in. Choosing the larger file size in ACR 6.3, means that Fractals has less work to do to bring it up to the desired image size.

One point; After I've completed all the editing and enlarging in CS5, I then open the file in ACR6.3 and inspect the image for noise as well as final sharpening- if needed. That last step has made a significant difference in the final product.

Zig
ACR6.3 offers a number of upsampling choices but my understanding is that too much can introduce unwanted artifacts. Does anyone know if that is a fact?
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Old Jan 25, 2011, 7:20 AM   #22
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ACR6.3 offers a number of upsampling choices but my understanding is that too much can introduce unwanted artifacts. Does anyone know if that is a fact?
Hi,

I'm not sure if it's fact or not. But, I've not noticed anything in my upsampled images that would bother me- to this point.

I just did a quick test, after reading your post. I took a photo that had been previously run through ACR. The original size was 8 x 10 376dpi. I upsampled it to 20 x 25 x 240dpi. and then cropped the same section of each image to compare. To me, it looks like rather than introducing artifacts, the software is magnifying what is already there.

Note: I did not do any post processing to the cropped images

Original Photo:



cropped area of original photo:



cropped area of upsampled image:

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Old Jan 25, 2011, 8:08 AM   #23
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Hi,

I'm not sure if it's fact or not. But, I've not noticed anything in my upsampled images that would bother me- to this point.
I always thought that dividing the dimensions of the photograph by the dpi, would give you the size of the picture at the end, without IQ loss.

ie. [email protected] would give you a 30"x30" print? (3000/100=30).

If someone asks for a specific dpi, then you can know the biggest print you can have without loosing IQ as well.

ie. [email protected] would give yo ua 10"x10" print without IQ loss.

Have I understood the principle of the thing?
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Old Jan 25, 2011, 1:16 PM   #24
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I always thought that dividing the dimensions of the photograph by the dpi, would give you the size of the picture at the end, without IQ loss.

ie. [email protected] would give you a 30"x30" print? (3000/100=30).

If someone asks for a specific dpi, then you can know the biggest print you can have without loosing IQ as well.

ie. [email protected] would give yo ua 10"x10" print without IQ loss.

Have I understood the principle of the thing?
Whew....this is why I just upload full-sized image files to Smugmug and let them do what they have to do in order to make the size print I want!

When it comes to this subject, for me, ignorance is bliss. I know just enough to get myself in trouble so I just let someone else handle it. I was working at learning how to use the object selection tool in Photoshop last night and was so wound up after two hours I needed a drink.
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